Talk:CXI

How 3DS system judge encryption type? --Matyapiro

Sorry the question is not understood. What do you mean? --Neimod

I think that he means "How does the 3DS decide what encryption method must be used" --Quincy 23:47, 29 May 2011 (CEST)

That question does not make sense. There are no decisions. It is always AES CTR. --Neimod

Sorry,how does the 3DS decide what key to use for encryption? --Matyapiro

If you figure that out, let us know, thanks. --Neimod 02:45, 1 June 2011 (CEST)

There's a common key used to generate output at compile time, when the cci/ctx files are made. Why do you say 128 bit AES CTR though? --Jl12

Because 128-bit AES CTR is used to encrypt those formats. --Neimod 15:40, 18 June 2011 (CEST)

I know *something* is used to encrypt but do we know it is 128 bit AES CTR? --Jl12

Frankly I don't think it was AES. I think it's using RSA for encryption. Besides it already used it once for the 2048-bit signature as you said. Wouldn't it make way more sense to also use it for the encryption scheme. --Jl12

Lol. --Neimod 16:06, 20 June 2011 (CEST)

What's funny? So I guess it's just based purely on speculation? You should say so. That way nobody believes something that isn't right. --Jl12 22:28, 20 June 2011 (CEST)

RSA is only used for the signature. After that a symmetric block cipher called AES is used in CTR mode. --Neimod 23:32, 20 June 2011 (CEST)

How did you get this data? Did you find some way to dump 3DS cartridges? --Popoffka 09:15, 1 June 2011 (CEST)

Yes, someone found a way to dump the data on 3DS cards. Unfortunately the method cannot be disclosed, and at this point dumping is not really useful since most of the information is encrypted. --Neimod 10:03, 1 June 2011 (CEST)

Do you have any method to run a Dump? and did you find the key for the ctrtool? --Stevechou

Nope on both questions. --Neimod 17:33, 25 June 2011 (CEST)

There's code in ctrtool that takes the AES counter value from some partition ID and type. I can't help but wonder, how do you know that the counter value is generated this way? And if we know that, isn't it a start to finding out the key? --Luigi2us 20:17, 25 June 2011 (CEST)